Question

operações com notações cientificas

Answer 1

Resposta:

Explicação passo-a-passo:

1)

A)

= 1,8.10^4 + 2,3.10^4

= 4,1.10^4

B)

= 2,3.10^(-5) + 5,6.10^(-5)

= 7,9.10^(-5)

C)

= 1,8.10^(-4) +2,6 . 10^(-5)

= 18.10^(-1).10^(-4) + 2,6.10^(-5)

= 18.10^(-5) + 2,6.10^(-5)

= 20,6.10^(-5)

= 2,06.10.10^(-5)

= 2,06.10^(-4)

D)

= 5,9.10^(-3) + 4,4.10^(-3)

= 10,3. 10^(-3)

= 1,03.10.10^(-3)

= 1,03.10^(-2)

E)

= 2,4.10^3 + 3,8.10^4

= 0,24.10.10^3 + 3,8 . 10^4

= 0,24.10^4 + 3,80 . 10^4

= 4,04.10^4

F)

= 9,8.10^4 + 3,4.10^3

= 98.10^(-1).10^4 + 3,4.10^3

= 98,0 + 3,4 . 10^3

= 101,4 . 10^3

= 1,014 . 10^2 . 10^3

= 1,014 . 10^5

2)

= 28000000 - 15000000

= 28.10^6 - 15.10^6

= 13.10^6

= 1,3 . 10 . 10^6

= 1,3.10^7

3)

= 1,67.10^(-24) + 3,95.10^(-22)

= 1,67.10^(-24) + 395.10^(-2).10^(-22)

= 1,67.10^(-24) + 395,00 .10^(-24)

= 396,67.10^(-24)

= 3,9667.10^(2).10^(-24)

= 3,9667.10^(-22)

4)

= 0,0000025 . 0,0000000002

= 25.10^(-7) .2.10^(-10)

= 50. 10^(-17)

= 5.10.10^(-17)

= 5.10^(-16)

5)

= 3,21.10^(-4) - 1,3.10^(-5)

= 32,1.10^(-1).10^(-4) - 1,3.10^(-5)

= 32,1.10^(-5) - 1,3.10^(-5)

= 30,8. 10^(-5)

= 3,08.10.10^(-5)

= 3,08.10^(-4)

6)

Pop = 45000000

Celulares = 54000000

Cel / hab

= 54000000 / 45000000

= 54/45 (:9)/(:9)

= 6/5

= 1,2 cel / hab

7)

X = 3200000

Y = 0,00002

X.y

= 32.10^5 . 2 . 10^(-5)

= 64. 10^(5-5)

= 64 . 10^0

= 64

Answer 2

$\large\boxed{\begin{array}{l}\sf{\underline{Um~n\acute{u}mero~est\acute{a}~em~notac_{\!\!,}\tilde{a}o~cient\acute{i}fica~quando}:}\\\sf{\checkmark~est\acute{a}~entre~1~e~10}\\\sf{\checkmark~est\acute{a}~escrito~como~pot\hat{e}ncia~de~10}\end{array}}$

$\large\boxed{\begin{array}{c}\tt{Quando~o~n\acute{u}mero~\acute{e}~superior~a~10~desloca-se}\\\tt{a~v\acute{i}rgula~para~esquerda~de~modo~que~o~n\acute{u}mero}\\\tt{esteja~entre~1~e~10~e~soma-se}\\\tt{ao~expoente~10~a~quantidade~de~casas~deslocadas}\end{array}}$

$\large\boxed{\begin{array}{c}\tt{Quando~o~n\acute{u}mero~\acute{e}~inferior~a~1~desloca-se}\\\tt{a~v\acute{i}rgula~para~direita~de~modo~que~o~n\acute{u}mero}\\\tt{esteja~entre~1~e~10~e~diminui-se}\\\tt{do~expoente~10~a~quantidade~de~casas~deslocadas}\end{array}}$

$\boxed{\begin{array}{l}\rm 1)\\\tt a)~\sf1,8\cdot10^4+2,3\cdot10^4=4,1\cdot10^4\\\tt b)~\sf2,3\cdot10^{-5}+5,6\cdot10^{-5}=7,9\cdot10^{-5}\\\tt c)~\sf1,8\cdot10^{-4}+2,6\cdot10^{-5}=1,8\cdot10^{-4}+26\cdot10^{-4}\\\sf=27,8\cdot10^{-4}=2,78\cdot10^{-3}\\\tt d)~\sf5,9\cdot10^{-3}+4,4\cdot10^{-3}=10,3\cdot10^{-3}\\\sf=1,03\cdot10^{-2}\\\tt e)~\sf2,4\cdot10^3+3,8\cdot10^4=0,24\cdot10^4+3,8\cdot10^4\\\sf=4,04\cdot10^4\end{array}}$

$\boxed{\begin{array}{l}\tt f)~\sf9,8\cdot10^4+3,4\cdot10^3=9,8\cdot10^4+0,34\cdot10^4\\\sf10,14\cdot10^4=1,014\cdot10^5\end{array}}$

$\large\boxed{\begin{array}{l}\rm 2)~\sf 28\,000-15\,000=13\,000=1,3\cdot10^5\end{array}}$

$\large \boxed{\begin{array}{l}\rm 3)~\sf1,67\cdot10^{-24}+3,95\cdot10^{-22}\\\sf=0,0167\cdot10^{-22}+3,95\cdot10^{-22}\\\sf=3,9667\cdot10^{-22}\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~a}}}}\end{array}}$

$\large\boxed{\begin{array}{l}\rm 4)\\\sf0,0000025\cdot0,0000000002\\\sf=2,5\cdot10^{-6}\cdot2\cdot10^{-10}\\\sf=5\cdot10^{-16}\end{array}}$

$\large\boxed{\begin{array}{l}\rm 5)~\sf3,21\cdot10^{-4}-1,3\cdot10^{-5}\\\sf=0,321\cdot10^{-5}-1,3\cdot10^{-5}\\\sf=-0,979\cdot10^{-5}\\\sf=-9,79\cdot10^{-4}\end{array}}$

$\boxed{\begin{array}{l}\rm 6)\\\sf54\,000\,000\div45\,000\,000=1,2 ~celulares/habitantes\end{array}}$

$\large\boxed{\begin{array}{l}\rm 7)\\\sf3\,200\,000\cdot0,00002\\\sf3,2\cdot10^6\cdot2\cdot10^{-5}\\\sf=6,4\cdot10^{1}=64\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~c}}}}\end{array}}$