Question

Opa alguém consegue me ajudar nesta tarefa?


1. Resolva as inequações:

a) 8x – 10 > 2x + 8

b) 2(3x +7) 100

f) 7x – 9 < 2x + 16

Answer 1

Resposta:

a)

$8x-10>2x+8\\8x-2x>8+10\\6x>18\\x>3$

b)

$2(3x+7)<-4x+8\\6x+14<-4x+8\\6x+4x<8-14\\10x<-6\\x < -\frac{6}{10}\\\\\ x<-\frac{3}{5}$

c)

$20- (2x+5)\leq 11+8x\\20-2x-5\leq 11+8x\\-2x-8x\leq 11-20+5\\-10x\leq -4\\x\leq \frac{-4}{-10}\\\\ x\leq \frac{2}{5}$

d)

$2x+5<-3x+40\\2x+3x<40-5\\5x<35\\x<7$

e)

$6(x-5)-2(4x+2)>100\\6x-30-8x-4>100\\-2x-34>100\\-2x>100+34\\-2x>134\\x>-\frac{134}{2} \\\\x>-67$

f)

$7x-9<2x+16\\7x-2x<16+9\\5x<25\\x<\frac{25}{5} \\\\x<5$