Question

Olá, alguém consegue desenvolver essa questão de limite?

c23cf356a1e424d9f128f533e4c706dc.docx

Answer 1

$L=\lim\limits_{n\to\infty}\dfrac{2n^3-n}{\sqrt{n^6+1}}\\ \\ \\ L=\lim\limits_{n\to\infty}\dfrac{\dfrac{2n^3-n}{n^3}}{\dfrac{\sqrt{n^6+1}}{n^3}}\\ \\ \\ L=\lim\limits_{n\to\infty}\dfrac{2-\dfrac{1}{n^2}}{\sqrt{1+\dfrac{1}{n^6}}}\\ \\ \\ L=\dfrac{2-0}{\sqrt{1+0}}\\ \\ \\ \boxed{L=2}$