Question

OIII ALGUEM ME AJUDA POR FAVOR PFVR PFVR PFVR

Answer 1

Resposta:

i⁵+i⁶+i⁷+i⁸+i⁹+i¹⁰+i¹¹+i¹²+i¹³+i¹⁴+i¹⁵+i¹⁶+i¹⁷+i¹⁸

n=18-5+1 =14

a₁=i⁵

q=i⁶/i⁵=i

Sₙ=a₁*(1-qⁿ)/(1-q)

S =  i⁵ *(1-i¹⁴)/(1-i)

*****i¹⁴ =(i²)⁷ =[[√(-1)]²]⁷=(-1)⁷ = -1

S =  i⁵ *(1-(-1))/(1-i)

S = 2i⁵/(1-i)

S=2i⁵/(1-i)  * (1+i)/(1+i)

S = 2i⁵(1+i)/(1-i²)

S = 2i⁵(1+i)/(1+1)

S = i⁵(1+i) =i⁵ + i⁶

******  i⁵ =i * i⁴ = i * [(√(-1))⁴]=i*1= i

******  i⁶= i*i⁵=i*i=-1

S =i⁵ + i⁶ =-1+i

⊕ -1+i