Question

oi Socorro alguem inteligente ne matematica​

Answer 1

Expressões algébricas:

• A)

$\sf -4x^4\cdot \left(2x^3-5x^2+6x-3\right)\\\\\\\sf =-4x^4\cdot \:2x^3-4x^4\left(-5x^2\right)-4x^4\cdot \:6x-4x^4\left(-3\right)\\\\\\\sf =-8x^7-\left(-20x^6\right)-24x^5-\left(-12x^4\right)\\\\\\\sf \boxed{\sf =-8x^7+20x^6-24x^5+12x^4}$

• B)

$\sf 3a^4b^5\cdot \left(-4a^2b^3+2a^5-3b^2\right)\\\\\\\sf 3a^4b^5\left(-4a^2b^3+2a^5-3b^2\right)=3a^4b^5\left(-4a^2b^3\right)+3a^4b^5\cdot \:2a^5+3a^4b^5\left(-3b^2\right)\\\\\\\sf 3a^4b^5\left(-4a^2b^3\right)+3a^4b^5\cdot \:2a^5+3a^4b^5\left(-3b^2\right)\\\\\\\boxed{\sf -12a^6b^8+6a^9b^5-9a^4b^7}$

• C)

$\sf \displaystyle \sf \frac{2}{3}x^5\cdot \left(\frac{-4}{5}x^7+\frac{1}{3}x^5-\frac{5}{7}x^3\right)\\\\\\\\\sf =\frac{2}{3}x^5\left(-\frac{4x^7}{5}+\frac{x^5}{3}-\frac{5x^3}{7}\right)\\\\\\\\\sf =\frac{2x^5\left(-\frac{4x^7}{5}+\frac{x^5}{3}-\frac{5x^3}{7}\right)}{3}\\\\\\\\\sf =\frac{\frac{2x^5\left(-84x^7+x^5\cdot \:35-75x^3\right)}{105}}{3}\\\\\\\sf =\frac{2x^5\left(-84x^7+x^5\cdot \:35-75x^3\right)}{105\cdot \:3}\\\\\\\boxed{\sf =\frac{2x^5\left(-84x^7+35x^5-75x^3\right)}{315}}$

• D)

$\sf -2ab^4c^3\cdot \left(-3a^2b^3c^5+8a^5b^6c^7\right)\\\\\\\sf -2ab^4c^3\left(-3a^2b^3c^5+8a^5b^6c^7\right)=-2ab^4c^3\left(-3a^2b^3c^5\right)-2ab^4c^3\cdot \:8a^5b^6c^7\\\\\\\sf -2ab^4c^3\left(-3a^2b^3c^5\right)-2ab^4c^3\cdot \:8a^5b^6c^7\\\\\\\boxed{\sf 6a^3b^7c^8-16a^6b^{10}c^{10}}$