Question

Oi me ajudaah???""x2+11x+28=0""

Answer 1

$x^{2} +11x+28=0$
Δ=$11^{2}$ -4.1.28
Δ=121-112
Δ= 9
x= -11±$\sqrt{9}$/2.1
x= -11+3=
x= -8/2
x = -4

x"= -11-3
x" = -14/2
x"= - 7

Answer 2

$x^{2} +11x+28=0= delta =b^{2} -4.a.c= delta= 11^{2} -4.1.28= delta=121-112=9 x1=11-+ \sqrt{9} /2=11-3/2=8/2=4 x2=11-+ \sqrt{9} /=11+3/2=14/2=7$