Question

obtenha quando existir os zeros das questões c) g(x)= x²-4x+3

Answer 1

g(x) = x² - 4x + 3


$\delta=b^2 - 4.a.c\\\delta=4^2-4.1.3\\\delta=16-12\\\delta=4$
$x=\frac{-b\pm\sqrt{delta}}{2a}\\x=\frac{-(-4)\pm\sqrt{4}}{2.1}\\x=\frac{4+2}{2}\\\\\boxed{x=3}$

$x' = \frac{4-2}{2}\\\\\boxed{x'=1}$

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