Question

obtenha em cada caso o valor real de x
log x ( 2x-3) = log x (-4x+8)
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Answer 1

logx(2x - 3) = logx(-4x + 8)

log(2x - 3)/log(x) = log(-4x+8)/log(x)

log(2x - 3) = log(8 - 4x)

2x-3=8 - 4x

6x = 11

X = 11/6