Obtenha as raízes da função f(x)= 49-x²/31
lulu5898:
ele está dividindo os dois msm
Soluções para a tarefa
Respondido por
1
Oi
![f(x)= \frac{49-x^2}{31} \\ \\ igualando \ a \ zero \\ \\ \frac{49-x^2}{31}=0 \\ \\ 49-x^2=31*0 \\ \\ 49-x^2=0 \\ \\ -x^2=-49 \\ \\ x^2=49 \\ \\ x= ^+_{-}\sqrt{49} \\ \\ x=^+_-7 \\ \\ \\ \\ \boxed{S= [-7 , 7]}](https://tex.z-dn.net/?f=f%28x%29%3D+%5Cfrac%7B49-x%5E2%7D%7B31%7D++%5C%5C++%5C%5C+igualando+%5C+a+%5C+zero+%5C%5C++%5C%5C+%5Cfrac%7B49-x%5E2%7D%7B31%7D%3D0+%5C%5C++%5C%5C+49-x%5E2%3D31%2A0+%5C%5C++%5C%5C+49-x%5E2%3D0+%5C%5C++%5C%5C+-x%5E2%3D-49+%5C%5C++%5C%5C+x%5E2%3D49+%5C%5C++%5C%5C+x%3D+%5E%2B_%7B-%7D%5Csqrt%7B49%7D++%5C%5C++%5C%5C+x%3D%5E%2B_-7+%5C%5C++%5C%5C++%5C%5C++%5C%5C+%5Cboxed%7BS%3D+%5B-7+%2C+7%5D%7D "f(x)= \frac{49-x^2}{31} \\ \\ igualando \ a \ zero \\ \\ \frac{49-x^2}{31}=0 \\ \\ 49-x^2=31*0 \\ \\ 49-x^2=0 \\ \\ -x^2=-49 \\ \\ x^2=49 \\ \\ x= ^+_{-}\sqrt{49} \\ \\ x=^+_-7 \\ \\ \\ \\ \boxed{S= [-7 , 7]}")
Espero que goste. Comenta depois :)
Espero que goste. Comenta depois :)
ah sim obggg :)
Perguntas interessantes