Question

obtenha as geratrizes das seguintes dizimas periodicas:
A) 0,35444...
B) 2,5424242...
C) 1,38181...
D) 0,314848...

Answer 1

$A) 0,35444... = \frac{354 - 35}{900} = \frac{319}{900}\\\\ B) 2,54242 ... = 2 + \frac{542 - 5}{990} = 2 + \frac{537}{990} = \frac{2517}{990} \\\\ C) 1,38181 ... = 1 + \frac{381 - 3}{990} = 1 + \frac{378}{990} = \frac{1368}{990} \\\\ D) 0,314848... = \frac{3148 - 31}{9900} = \frac{3117}{9900}$