Question

Obtenha a p.g (an) de termos não nulos e razão q=2/3 tal que A6=A1.A4

Answer 1

an = a1 * (2/3)^n-1

a1 * (2/3)^5 = a1^2 * (2/3)^3
(2/3)^5/(2/3)^3 = a1
(2/3)^2 = a1

4/9 = a1

( 4/9, 8/27, 16/81, 32/243, 64/729, 128/2187, ...)