Question

obtenha a forma reduzida e a raiz:

(x+1)×(x-2)=-7x-10

Answer 1

$(x-1)(x-2)=-7x-10 \\ \\ x^{2} -2x+x-2=-7x-10 \\ \\ x^{2} -x-2+7x+10=0 \\ \\ x^{2} +6x+8=0$

Utilizando a fórmula de Bhaskara

delta = 36-4.1.8=36-32=4

$\sqrt{delta} = \sqrt{4} = 2$

$x_{1} = \frac{-6+2}{2} = \frac{-4}{2} = -2 \\ \\ x_{2} = \frac{-6-2}{2} = \frac{-8}{2} =-4$

Answer 2

(x + 1).(x - 2) = - 7x - 10
x² - 2x + x - 2 = - 7x - 10
x² - x - 2 = - 7x - 10
x² - x + 7x - 2 + 10 = 0
x² + 6x + 8 = 0
a = 1; b = 6; c = 8

Δ = b² - 4ac
Δ = (6)² - 4.1.8
Δ = 36 - 32
Δ = 4

x = - b +/- √Δ  = -  6 +/- √4
          2a                  2.1

x = - 6 + 2 = - 4/2 = - 2
           2

x = - 6 - 2 = - 8/2 = - 4
          2

R.: x = - 2 e x = - 4