Question

Obtenha a equacao geral da reta que passa por A(-3,4) e apresenta coeficiente angular m=-1

Answer 1

A(-3;4)
m=-1

(y-y°)=m(x-x°) ---->

$(y-4)=-1(x-(-3))\to \\\\(y-4)=-1(x+3)\to \\\\y-4=-x-3\to \\\\ y+x-4+3=0\to \\\\y+x-1=0\to Geral\\\\\\ y=-x+1\to Reduzida$

Answer 2

m = -a/b --> -a/b = -1 --> -a = -b --> a = b
y = ax+b
4 = -3a+b
4 = -3a+a
4 = -2a
2a = -4
a = -4/2
a = -2
a = b
-2x -y -2 = 0