obtenha a equação da reta que tem m=3/4 e passa por A(2, -5)?
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Deve-se usar a seguinte formula matemática, e substituir os termos, para obter a equação da reta.
![y - y_a = m * (x - x_a) \\\\
y - (-5) = \frac{3}{4} * (x - 2) \\\\
y + 5 = \frac{3x}{4} - \frac{6}{4} \\\\
y = \frac{3x - 6 - 20}{4} \\\\\
y = \frac{3x - 26}{4} \\\\
\boxed{y = \frac{3x}{4} - \frac{13}{2}}](https://tex.z-dn.net/?f=y+-+y_a+%3D+m+%2A+%28x+-+x_a%29+%5C%5C%5C%5C+%0Ay+-+%28-5%29+%3D+%5Cfrac%7B3%7D%7B4%7D+%2A+%28x+-+2%29+%5C%5C%5C%5C+%0Ay+%2B+5+%3D+%5Cfrac%7B3x%7D%7B4%7D+-+%5Cfrac%7B6%7D%7B4%7D+%5C%5C%5C%5C+%0Ay+%3D+%5Cfrac%7B3x+-+6+-+20%7D%7B4%7D+%5C%5C%5C%5C%5C%0Ay+%3D+%5Cfrac%7B3x+-+26%7D%7B4%7D+%5C%5C%5C%5C%0A%5Cboxed%7By+%3D+%5Cfrac%7B3x%7D%7B4%7D+-+%5Cfrac%7B13%7D%7B2%7D%7D+%0A "y - y_a = m * (x - x_a) \\\\
y - (-5) = \frac{3}{4} * (x - 2) \\\\
y + 5 = \frac{3x}{4} - \frac{6}{4} \\\\
y = \frac{3x - 6 - 20}{4} \\\\\
y = \frac{3x - 26}{4} \\\\
\boxed{y = \frac{3x}{4} - \frac{13}{2}}")
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