Obtenha a equação da reta que passa pelos pontos : ( 5,2 ) e ( 2,4 )
Soluções para a tarefa
Respondido por
3
Coeficiente angular da reta:
m=y2-y1/x2-x1=
4-2/2-5=
m=2/-3
y-y1=m(x-x1)
y-2=2/-3(x-5)
y-2=-2/3x+10/3=
y-2+2/3x-10/3=0
y+2/3x-16/3=0
2/3x+y-16/3=0
m=y2-y1/x2-x1=
4-2/2-5=
m=2/-3
y-y1=m(x-x1)
y-2=2/-3(x-5)
y-2=-2/3x+10/3=
y-2+2/3x-10/3=0
y+2/3x-16/3=0
2/3x+y-16/3=0
Perguntas interessantes