Obtenha a equação da reta pelos pontos:
A- A (0,2) e B (1,3)
B- A (3,2) e B (0,1)
C- A (1,1) e B (2,-2)
Soluções para a tarefa
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tendo algum conhecimento básico em matriz,
A)![\left[\begin{array}{ccc}x&y&1\\0&2&1\\1&3&1\end{array}\right] \left[\begin{array}{ccc}x&y&1\\0&2&1\\1&3&1\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26amp%3By%26amp%3B1%5C%5C0%26amp%3B2%26amp%3B1%5C%5C1%26amp%3B3%26amp%3B1%5Cend%7Barray%7D%5Cright%5D+)
(2x+y)-(2+3x)
2x+y-2-3x=0
y-x-2=0
y=x+2
B)![\left[\begin{array}{ccc}x&y&1\\3&2&1\\0&1&1\end{array}\right] \left[\begin{array}{ccc}x&y&1\\3&2&1\\0&1&1\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26amp%3By%26amp%3B1%5C%5C3%26amp%3B2%26amp%3B1%5C%5C0%26amp%3B1%26amp%3B1%5Cend%7Barray%7D%5Cright%5D+)
(2x+3)-(x+3y)
2x+3-x-3y=0
-3y+x+3=0
-3y=-x-3
y=
y=
C)
(x+2y-2)-(2-2x+y)
x+2y-2-2+2x-y=0
y+3x-4=0
y= -3x+4
A)
(2x+y)-(2+3x)
2x+y-2-3x=0
y-x-2=0
y=x+2
B)
(2x+3)-(x+3y)
2x+3-x-3y=0
-3y+x+3=0
-3y=-x-3
y=
y=
C)
(x+2y-2)-(2-2x+y)
x+2y-2-2+2x-y=0
y+3x-4=0
y= -3x+4
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