Question

Observe o triângulo abaixo: A medida dos lados AC = 4 cm e do lado BC do triângulo a seguir é:



12

6

8

3 √2

Answer 1

$\large\boxed{\begin{array}{l}\underline{\rm Pela~lei~dos~senos:}\\\sf\dfrac{BC}{sen(45^\circ)}=\dfrac{3\sqrt{2}}{sen(30^\circ)}\\\sf BC\cdot sen(30^\circ)=3\sqrt{2}\cdot sen(45^\circ)\\\sf BC\cdot\dfrac{1}{\backslash\!\!\!2}=3\sqrt{2}\cdot\dfrac{\sqrt{2}}{\backslash\!\!\!2}\\\sf BC=3\sqrt{2}\cdot\sqrt{2}\\\sf BC=3\sqrt{2^{\backslash\!\!\!2}}\\\sf BC=3\cdot2\\\sf BC=6\end{array}}$