Question

o12°termo da PG (3,9.27...)

Answer 1

$PG~\{~3,9,27,...~\}\\\\\\a_1=3\\q=9:3=3\\ n=9\\ a_9=?\\\\\\ a_n=a_1\times q^{n-1}\\\\\\ a_9=3\times 3^{9-1}\to\\\\ a_9=3\times 3^8\to\\\\a_9=3\times 6561\to\\\\ \boxed{a_9=19683}$