Question

O vértice da parábola f(x) = -x² + x – 3, é:
a) V (3,4) b) V (12, -114) c) V ( -4,3) d) (−12,114) e) -1,-2)

Answer 1

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$\boxed{\begin{array}{l}\sf f(x)=-x^2+x-3\\\sf\Delta=b^2-4ac\\\sf\Delta=1^2-4\cdot(-1)\cdot(-3)\\\sf\Delta=1-12\\\sf\Delta=-11\\\sf x_V=-\dfrac{b}{2a}\\\sf x_V=-\dfrac{1}{2\cdot(-1)}\\\sf x_V=\dfrac{1}{2}\\\sf y_V=-\dfrac{\Delta}{4a}\\\sf y_V=-\dfrac{-11}{4\cdot(-1)}\\\sf y_V=-\dfrac{11}{4}\\\sf V\bigg(\dfrac{1}{2},-\dfrac{11}{4}\bigg)\\\sf o~gabarito~est\acute a~incorreto\\\sf \end{array}}$