Question

o vertice da parabola definida pela função f(×)=-×2+6×-9

Answer 1

-x^2+6x-9=0
delta=b^2-4ac
delta=6^2-4.(-1).(-9)
delta=36-36
delta=0
xv=-b/2a
xv=-6/2.(-1)
xv=-6/-2
xv=3
yv=-delta/4a
yv=-0/4.(-1)
yv=-0/-4
yv=0
(3, 0)