O VÉRTICE DA PARABOLA a)y=x²-4x+13 É???
Soluções para a tarefa
Respondido por
0
Na abscissa,
![\\X_v=\frac{-b}{2a}\\\\X_v=\frac{-(-4)}{2\cdot1}\\\\X_v=\frac{4}{2}\\\\\boxed{X_v=2} \\X_v=\frac{-b}{2a}\\\\X_v=\frac{-(-4)}{2\cdot1}\\\\X_v=\frac{4}{2}\\\\\boxed{X_v=2}](https://tex.z-dn.net/?f=%5C%5CX_v%3D%5Cfrac%7B-b%7D%7B2a%7D%5C%5C%5C%5CX_v%3D%5Cfrac%7B-%28-4%29%7D%7B2%5Ccdot1%7D%5C%5C%5C%5CX_v%3D%5Cfrac%7B4%7D%7B2%7D%5C%5C%5C%5C%5Cboxed%7BX_v%3D2%7D)
Na ordenada,
![\\Y_v=\frac{-\Delta}{4a}\\\\Y_v=\frac{-(b^2-4ac)}{4\cdot1}\\\\Y_v=\frac{-(16-52)}{2}\\\\Y_v=\frac{-(-36)}{4}\\\\Y_v=\frac{36}{4}\\\\\boxed{Y_v=9} \\Y_v=\frac{-\Delta}{4a}\\\\Y_v=\frac{-(b^2-4ac)}{4\cdot1}\\\\Y_v=\frac{-(16-52)}{2}\\\\Y_v=\frac{-(-36)}{4}\\\\Y_v=\frac{36}{4}\\\\\boxed{Y_v=9}](https://tex.z-dn.net/?f=%5C%5CY_v%3D%5Cfrac%7B-%5CDelta%7D%7B4a%7D%5C%5C%5C%5CY_v%3D%5Cfrac%7B-%28b%5E2-4ac%29%7D%7B4%5Ccdot1%7D%5C%5C%5C%5CY_v%3D%5Cfrac%7B-%2816-52%29%7D%7B2%7D%5C%5C%5C%5CY_v%3D%5Cfrac%7B-%28-36%29%7D%7B4%7D%5C%5C%5C%5CY_v%3D%5Cfrac%7B36%7D%7B4%7D%5C%5C%5C%5C%5Cboxed%7BY_v%3D9%7D)
Na ordenada,
Perguntas interessantes
Português,
5 meses atrás
Matemática,
5 meses atrás
Matemática,
1 ano atrás
Matemática,
1 ano atrás
Sociologia,
1 ano atrás