Question

O valor do lim (x tende a 2) x³-x²-2x/x²-3x+2 é

Answer 1

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Solução!

$\displaystyle \lim_{n \to 2} \frac{ x^{3}- x^{2} -2x }{ x^{2} -3x+2}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ x(x^{2}- x -2) }{ x^{2} -3x+2}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ x(x-2)(x +2) }{ (x-2)(x-1)}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ x(x +2) }{(x-1)}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ 2(2 +2) }{(2-1)}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ 2(4) }{(1)}\\\\\\ \displaystyle \lim_{n \to 2} \frac{ 8 }{1}\\\\\\ \displaystyle \lim_{n \to 2}8$


$\boxed{Resposta:\displaystyle \lim_{n \to 2} \frac{ x^{3}- x^{2} -2x }{ x^{2} -3x+2}=8}$

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