Question

O valor de $\sqrt{67- \sqrt{6+ \sqrt{9} } }$ é igual a:

Answer 1

$\sqrt{67- \sqrt{6+ \sqrt{9} } }$

= $\sqrt{67- \sqrt{6+3} }$

= $\sqrt{67- \sqrt{9} }$

= $\sqrt{67-3}$

= $\sqrt{64}$

= 8

Answer 2

√(67-√(6+√9)) = √(67-√(6+3)) = √(67-√9) = √67-3 = √64 = 8