Matemática, perguntado por alissonsantos23, 7 meses atrás

o valor de sen1200 é igaul a:​

Soluções para a tarefa

Respondido por SwiftTaylor
4

\sf sin \left(1200^{\circ \:}\right)\\\\\\\sf sin \left(x\right)=cos \left(90^{\circ \:}-x\right)\\\\\\\sf sin \left(1200^{\circ \:}\right)=cos \left(90^{\circ \:}-1200^{\circ \:}\right)\\\\\\\sf cos \left(90^{\circ \:}-1200^{\circ \:}\right)\\\\\\\sf cos \left(-1110^{\circ \:}\right)\\\\\\\sf \left(-1110^{\circ \:}\right)=cos \left(1110^{\circ \:}\right)\\\\\\\sf cos \left(30^{\circ \:}\right)\\\\\\\boxed{\sf \frac{\sqrt{3}}{2}}

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