Question

O valor de log16 (24, 96)2 – log4 (3, 12) é:

Answer 1

Mudança de base 
2(log 16 ( 24,96) - log 4 (3,12)
2(㏒ 4 (24,96)/ log 4 16) - ㏒ 4 (3,12)
2(log 4 (24,96)/2) - log 4 (3,12)
log 4 (24,96) - log 4 (3,12), se 24,96 = 8.(3,12) ,logo temos.
log 4 ( 8.(3,12)) - log 4 (3,12)
log 4 8 + log 4 (3,12) - log 4 (3,12)
log 4 8 ; 4× = 8
             2²× = 2³
               2.x = 3
                  x = 3/2