Question

O valor de Delta na equação ( 2x + 8)² é? (1,0)
A) 9
B) 16
C) 0
D) 36
E) 25​

Answer 1

Resposta:

(2x +8)^2

(2x+8)*(2x+8)

4x^2 + 16x +16x +64

4x^2 + 32x + 64

x = b^2 - 4ac

x = 32^2 -4(4)(64)

x = 1024 - 1024

∆ = -b +-√∆/2a

∆ = -32 +- √0/2*4

∆ = -32/8

∆ = -4