Question

o valor de 2x^0+x^3/4+18x^-0,5. Quando x=81,é:

Answer 1

$2x^0+ \sqrt[4]{x^3} + \frac{18}{ \sqrt{x} }\\ =2\cdot81^0+ \sqrt[4]{81^3} + \frac{18}{ \sqrt{81} }\\ =2\cdot1+ 27 + \frac{18}{9}\\ =2+ 27 + 2\\ =31$