Question

O valor das raízes da equação
${x}^{2} + 2x - 48 = 0$
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Answer 1

Equação do 2° Grau!

x² + 2x - 48 = 0

A= 1
B= 2
C= - 48

∆= b² - 4ac

∆= 2² - 4 • 1 • ( - 48)
∆= 4 + 192
∆= 196

x= - b ± √∆/2a

x= - 2 ± √196 / 2 • 1
x= - 2 ± 14 / 2

x'= - 2 + 14/2 = 12/2 = 6
x''= - 2 - 14/2 = - 16/2 = - 8

S=( -8 , 6)

Answer 2

Olá, bom dia!

Vamos utilizar a fórmula de Bhaskara.

$x^2+2x-48=0\\\\Coeficientes:\;a=1,\;b=2\;e\;c=-48\\\\\Delta=b^2-4ac\\\Delta=2^2-4\cdot1\cdot(-48)\\\Delta=4+192\\\Delta=196\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-2\pm\sqrt{196}}{2\cdot1}\\\\x=\dfrac{-2\pm14}{2}\\\\x_1=\dfrac{-2+14}{2}=\dfrac{12}{2}=6\\\\x_2=\dfrac{-2-14}{2}=\dfrac{-16}{2}=-8$



Espero ter ajudado.
Bons estudos! :)