Question

O valor da integral ∫³∫²(4-y²)dy.dx é:
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Answer 1

$\int\limits^3_0 { \int\limits^2_0 {4-y^2} \, dy } \, dx \\\\\\ \int\limits^2_0 {4-y^2} \, dy=\left[4y-\dfrac{y^3}{3}\right]^2_0=8-\dfrac83=\dfrac{16}{3}\\\\ \int\limits^3_0 { \dfrac{16}{3}} \, dx=\left[\dfrac{16x}{3}\right]^3_0=16$