Question

O valor da expressão $<var>\frac{(-3)^{40} +3.(-3)^{39}-(-3)^{2}-3^{2}+3}{[(-2^{3})^{2}-(-7)^{2}].0,02}</var>$ é:

COLOCAR DESENVOLVIMENTO!!!

 

a) 1

b) -50

c) -10

d) -30

e) 15

Answer 1

Olá, Gabreu.

 

$<var>\frac{(-3)^{40} +3.(-3)^{39}-(-3)^{2}-3^{2}+3}{[(-2^{3})^{2}-(-7)^{2}].0,02}=\\\\ =\frac{\overbrace{(-3).(-3)^{39} +3.(-3)^{39}}^{=0}-9-9+3}{[(-8)^{2}-49].\frac2{100}}=\\\\ =\frac{-15}{[64-49].\frac1{50}}=\\\\ =-\frac{15}{15}\cdot 50=\\\\ =\boxed{-50} </var>$

 

Resposta: letra "b"