Question

o valor da expressão ( log2 4+log3√27-log3 1)2 é?

Answer 1

(log 2 4 + log 3 V27 - log 3 1)^2=

log de 4 na base 2= 
2^x=4
2^x=2^2
x=2

log de V27 na base 3=
3^y=V27
3^y=(27)^1/2
3^y=(3^3)^1/2
3^y=3^3/2
y=3/2

log de 1 na base 3=
3^w=1
3^w=3^0
w=0

(log 2 4 + log 3V27-log 3 1)^2
(2+3/2-0)^2=
(4/2+3/2)^2
(7/2)^2=
49/4