Question

O valor correto da expressão E= log2^8+0,001/10000+ 1/2^-3 é

Answer 1

Propriedades utilizadas:

◽ $\mathsf{\log _a\left(a\right)=1}$ 

◽ $\mathsf{\log _b\left(a^c\right)=c\cdot \log _b\left(a\right)}$

◽ $\mathsf{a^{-b}=\dfrac{1}{a^b}}$

◽ $\mathsf{\dfrac{a^b}{a^c}=a^b\cdot a^{-c}=a^{b+\left(-c\right)}=a^{b-c}}$
- - - - -

Resolução:

$\mathsf{E=\log _2\left(8\right)+\dfrac{0.001}{10000}+\dfrac{1}{2^{-3}}}\\\\\\\mathsf{E=\log _2\left(2^3\right)+\dfrac{10^{-3}}{10^4}+2^3}\\\\\\\mathsf{E=3\log _2\left(2\right)+\left(10^{-3}\cdot 10^{-4}\right)+2^3}\\\\\\\mathsf{E=\left(3\cdot 1\right)+10^{-7}+2^3}\\\\\\\mathsf{E=3+10^{-7}+8}\\\\\\\mathsf{E=11+10^{-7}}\\\\\\\mathsf{E=11+0,00000001}\\\\\\\boxed{\mathsf{E=11,00000001}}\: \: \checkmark$

Answer 2

Resposta:

letra b no plurall

Explicação passo-a-passo: