o vagao de um trem possui seis portas . de quantas maneiras distintas um passageiro pode entra no trem e sair dele por uma porta diferente da que entrou
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Solution :-
We can simply solve this mathematical problem using the following process:
using the idea of permutation and combinations, we can determine how many distinct ways there are for a guy to enter the room by one door and exit it through a different door, as seen below;
= × 2
Since each pair of door can be tallied twice since one door is utilized for entry in the first case and them for exit in the second , the number ( 6c2 ) reflects the potential paired combinations for the room's six doors.
= 6! / ( 4! 2! ) × 2
= 6! / 4!
= 5 × 6
= 30
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