Question

o suplemento de 130 graus 22' 53''

Answer 1

1° = 60'
1' = 60"

1' --- 60"
x' --- 53"

x' = 53/60

22 + 53/60 =
22 x 60 + 53 / 60 =
1320 + 53 / 60 =
1373' / 60

1° ----- 60'
x° ----- 1373'/60

x = (60/1) / (1373/60)
x = 60 x 60 / 1373
x = 3600° /1373

130 + 3600/1373 =
130 x 1373 + 3600 / 1373 =
178490 + 3600 / 1373 =
182090° / 1373

Suplemento:

182090/1373 + x = 180
182090 + 1373x / 1373 = 180
182090 + 1373x = 1373.180
1373x = 247140 - 182090
x = 65050 / 1373
→ x = 47,38°

1° ----- 60'
0,38° --- x'

x = 60 . 0,38
x = 22,8'

1' ----- 60"
0,8' --- x"

x = 60 x 0,8
x = 48"


Resposta: 47° 22' 48"