Question

O sistema abaixo é: ( alguem pode me ajudar)

Answer 1

Resolver pela regra de Cramer

$D= \left[\begin{array}{ccccc}1&1&3&1&1\\3&-2&4&3&-2\\2&-3&1&2&-3\end{array}\right] \\ \\ \\ D=-2+8-27-(-12-12+3) \\ D=-2+8-27+12+12-3 \\ D=32-32=0$ 


$D_X= \left[\begin{array}{ccccc}-5&1&3&-5&1\\0&-2&4&0&-2\\5&-3&1&5&-3\end{array}\right] \\ \\ \\ D_X=+10+20+0-(-30+60+0) \\ D_X=+10+20+30-60 \\ D_X=+60-60=0$ 


$D_Y= \left[\begin{array}{ccccc}1&-5&3&1&-5\\3&0&4&3&0\\2&5&1&2&5\end{array}\right] \\ \\ \\ D_Y=0-40+45-(0+20-15) \\ D_Y=-40+45-20+15 \\ D_Y=-60+60 \\ D_Y=0$ 


$D_Z= \left[\begin{array}{ccccc}1&1&-5&1&1\\3&-2&0&3&-2\\2&-3&5&2&-3\end{array}\right] \\ \\ \\ D_Z=-10+0+45-(+20+0+15) \\ D_Z=-10+45-20-15 \\ D_Z=-45+45 \\ D_Z=0$ 
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$como \\ D=0 \\ D_X=0 \\ D_Y=0 \\ D_Z=0 \\ \\ sistema~~\acute{e}~~poss\acute{i}vel~~e~~inderterminado\mapsto Letra~~B$