Question

o resultado de lim 5x²-4x+3 / 3x-2 quando x tende a infinito

Answer 1

$\lim\limits_{x\to\infty}\dfrac{5x^2-4x+3}{3x-2}=\lim\limits_{x\to\infty}\dfrac{x\left(5x-4+\frac{3}{x}\right)}{x\left(3-\frac{2}{x}\right)}=\lim\limits_{x\to\infty}\dfrac{5x-4+\frac{3}{x}}{3-\frac{2}{x}}=\\\\\\=\dfrac{5(\infty)-4+\frac{3}{(\infty)}}{3-\frac{2}{\infty}}=\dfrac{5(\infty)-4+0}{3-0}=\bold{\infty}$