Question

O quociente (7 √3 - 5 √48 + 2 √192) dividido por 3√3 e igual a:

Answer 1

$\frac{7 \sqrt{3}-5 \sqrt{2^4.3}+2 \sqrt{2^6} }{3 \sqrt{3} } = \frac{7 \sqrt{3}-20 \sqrt{3} +16 }{3 \sqrt{3} } =$

$\frac{-13 \sqrt{3}+16 }{3 \sqrt{3} }= \frac{-13+16}{3} = \frac{3}{3} = 1$

Answer 2

(7√3-5√48-2√198)÷3√3=-29.248077