Question

o que eu faço nesse caso ?

Answer 1

$log_{ \frac{125}{27} } 0,6=x \\ \\ (\frac{125}{27}) ^{x} =0,6 \\ \\ ( \frac{ 5^{3} }{3^3} )^{x} =0,6 \\ \\ ( \frac{5}{3} ^{3} )^{x} = \frac{6}{10} \\ \\ ( \frac{5}{3} )^{3x} = \frac{3}{5} \\ \\ ( \frac{5}{3} )^{3x} = ( \frac{5}{3} )^{-1} \\ \\ 3x=-1 \\ \\ x=- \frac{1}{3}$