O produto escalar entre u e v considerando u=(3,3,3) e v=(-1,-5,4) está corretamente expresso na alternativa
a) 4
b) 2
c) -6
d) -1
e) 6
andresccp:
-3 -15 + 12
Soluções para a tarefa
Respondido por
7
Boa tarde Roger!
Solução!
![\vec{u}=(3,3,3)~~~~~~~~~~~~\vec{v}=(-1,-5,4)\\\\\\
Fazendo!\\\\\\\
\vec{u} \times \vec{v}\\\\\\\
(3,3,3) \times (-1,-5,4)\\\\\
(-3-15+12)\\\\\\\
(-18+12)=-6\\\\\\\\\\\
\boxed{Resposta:~~-6~~\boxed{Alternativa~~C}}](https://tex.z-dn.net/?f=%5Cvec%7Bu%7D%3D%283%2C3%2C3%29%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%5Cvec%7Bv%7D%3D%28-1%2C-5%2C4%29%5C%5C%5C%5C%5C%5C%0AFazendo%21%5C%5C%5C%5C%5C%5C%5C%0A%5Cvec%7Bu%7D+%5Ctimes+%5Cvec%7Bv%7D%5C%5C%5C%5C%5C%5C%5C%0A%283%2C3%2C3%29+%5Ctimes+%28-1%2C-5%2C4%29%5C%5C%5C%5C%5C%0A%28-3-15%2B12%29%5C%5C%5C%5C%5C%5C%5C%0A%28-18%2B12%29%3D-6%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A%7E%7E-6%7E%7E%5Cboxed%7BAlternativa%7E%7EC%7D%7D+ "\vec{u}=(3,3,3)~~~~~~~~~~~~\vec{v}=(-1,-5,4)\\\\\\
Fazendo!\\\\\\\
\vec{u} \times \vec{v}\\\\\\\
(3,3,3) \times (-1,-5,4)\\\\\
(-3-15+12)\\\\\\\
(-18+12)=-6\\\\\\\\\\\
\boxed{Resposta:~~-6~~\boxed{Alternativa~~C}}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
Muito obrigado amigo !
Dê nada!
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