o perímetro de um triangulo retangulo mede 12 cm seus lados medem x, x+1, x+2. Determine a area desse triangulo
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p = x + (x + 1) + (x + 2) ------ 12 = x + x + 1 + x + 2 ------ 12 = 3x + 3
3x = 12 - 3 ----- 3x = 9 ----- x = 9/3 ------ x = 3
b = x ----- b = 3 cm
c = x+ 1 ---- c = 3 + 1 ------- c = 4 cm
a = x + 2 ----- a = 3 + 2 ---- a = 5 cm
A = (b. c)/2 --- A = (3 . 4)/2 --- A = (3 . 4)/2 --- A = 12/2 ----- A = 6 cm
3x = 12 - 3 ----- 3x = 9 ----- x = 9/3 ------ x = 3
b = x ----- b = 3 cm
c = x+ 1 ---- c = 3 + 1 ------- c = 4 cm
a = x + 2 ----- a = 3 + 2 ---- a = 5 cm
A = (b. c)/2 --- A = (3 . 4)/2 --- A = (3 . 4)/2 --- A = 12/2 ----- A = 6 cm
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