Question

O oitavo termo da PG ( 256,128 ,64 ,.....), é?

Answer 1

2 ---> resposta

Explicação passo-a-passo:

256,128,64,32,16,8,4,2,1

Answer 2

Resposta:

$a_8=2$

Explicação passo-a-passo:

$a_n=a_1.q^n^-^1\\\\n=8\\\\q=\frac{64}{128} =\frac{1}{2}\\\\a_8=256.(\frac{1}{2} )^8^-^1\\\\a_8=2^8.(\frac{1}{2})^7\\\\a_8=2^8.2^-^7\\\\a_8=2^1\\\\a_8=2$