Question

o numero da raiz da equação $3y^{4} -22^{2} -45=0$, é:

Answer 1

Lembrando que qualquer número real elevado a um expoente par é um número positivo

$3y^4-22^2-45=0\\\\3y^4-484-45=0\\\\3y^4-529=0\\\\3y^4=529\\\\y^4=\dfrac{529}{3}$
$y=\pm~\sqrt[4]{\dfrac{529}{3}}\\\\\\y=\pm~\dfrac{\sqrt[4]{529}}{\sqrt[4]{3}}\\\\\\y=\pm~\dfrac{\sqrt[4]{23^2}}{\sqrt[4]{3}}\\\\\\y=\pm~\dfrac{23^{\frac{2}{4}}}{\sqrt[4]{3}}\\\\\\y=\pm~\dfrac{23^{\frac{1}{2}}}{\sqrt[4]{3}}\\\\\\\fbox{ y=\pm~\dfrac{\sqrt{23}}{ \sqrt[4]{3}} }$


$S=\begin{Bmatrix}-\dfrac{\sqrt{23}}{\sqrt[4]{3}}~,~~\dfrac{\sqrt{23}}{\sqrt[4]{3}} \end{Bmatrix}$