Question

O mmc entre 6,20,50,100 e 125

Answer 1

Após resolver os cálculos, concluímos que o mínimo múltiplo comum "m.m.c" é:

$\therefore\boxed{\mathsf{ m\cdot m\cdot c(6,20,50,100 ~e~ 125)=1500}}$

Decomposição Simultânea:

$\boxed{\begin{array}{c|c}\sf n_1,n_2,n_3\,...&\sf N\acute{u}meros \\ &\sf Primos \\\\\end{array}}$

Resolvendo:

$\sf\begin{array}{c|c}\sf 6,20,50,100 ,125&\sf2\\\sf3,10,25,50,125&\sf2\\\sf3,5,25,25,125&\sf3\\\sf1,5,25,25,125&\sf5\\\sf1,1,5,5,25&\sf5\\\sf1,1,1,1,5&\sf5\\\sf1,1,1,1,1\end{array}\Longrightarrow 2^2\cdot3\cdot5^3=1500$

$\boxed{\boxed{\mathsf{m\cdot m\cdot c(6,20,50,100~ e ~125)=1500}}}$

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