Question

o logaritmo de raiz de 3 na base 27

Answer 1

$log_{27} \sqrt{3}$

Pra resolver é só pensar, 27 elevado a quem dá √3?

$27^{x} = \sqrt{3}$

$3^{3x} = 3^{ \frac{1}{2} }$

3x =  1  -->  x = 1
         2               6

$log_{27} \sqrt{3}$   =  1/6

Answer 2

$log_{27} \sqrt{3}$

$27^{x}= \sqrt{3}$

$(3^{3})^{x}=3^{ \frac{1}{2} }$

$3x= \frac{1}{2}$

$x= \frac{ \frac{1}{2} }{3}$

$x= \frac{1}{2} . \frac{1}{3}$

$x= \frac{1}{6}$