Question

O lado de um triangulo equilátero inscrito mede 5√3, o raio do circulo então medirá?

Answer 1

$L=5\sqrt{3}\\R=?$
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$cos~30\º=\dfrac{(\dfrac{L}{2})}{R}~~\therefore~~cos~30\º=\dfrac{L}{2R}~~\therefore~~\dfrac{\sqrt{3}}{2}=\dfrac{5\sqrt{3}}{2R}~~\therefore~~\dfrac{1}{1}=\dfrac{5}{R}\\\\\boxed{\boxed{R=5}}$