Matemática, perguntado por kj305381, 4 meses atrás

o dobro da menor raiz da equação do 2 grau dada po x-6x=-8 e?​

Soluções para a tarefa

Respondido por CyberKirito
3

\Large\boxed{\begin{array}{l}\rm O\,dobro\,da\,menor\,ra\acute iz\,da\,equac_{\!\!,}\tilde ao\\\rm do\,2^o\,grau\,dada\,por\,x^2-6x=-8~\acute e?\\\underline{\boldsymbol{soluc_{\!\!,}\tilde ao\!:}}\\\sf x^2-6x=-8\\\sf x^2-6x+8=0\\\sf\Delta=b^2-4ac\\\sf\Delta=(-6)^2-4\cdot1\cdot8\\\sf\Delta=36-32\\\sf\Delta=4\\\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\\sf x=\dfrac{-(-6)\pm\sqrt{4}}{2\cdot1}\end{array}}

\Large\boxed{\begin{array}{l}\sf x=\dfrac{6\pm2}{2}\begin{cases}\sf x_1=\dfrac{6+2}{2}=\dfrac{8}{2}=4\\\\\sf x_2=\dfrac{6-2}{2}=\dfrac{4}{2}=2\end{cases}\\\underline{\rm o\,dobro\,da\,menor\,ra\acute iz\,\acute e:}\\\sf 2\cdot2=4\end{array}}

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