o coeficiente regular da reta (r) é -1 sabe se que e ela passa pelos pontos A= (5, 0) e B= (0, k)
danielfalves:
Coeficiente Angular
Soluções para a tarefa
Respondido por
0
m => Coeficiente angular
![m= \dfrac{y_B-y_A}{x_B-x_A} \\\\\\m= \dfrac{k-0}{0-5}\\\\\\m= -\dfrac{k}{5}\\\\\\m=-1\\\\\\-1= -\dfrac{k}{5} \\\\\\k=5 m= \dfrac{y_B-y_A}{x_B-x_A} \\\\\\m= \dfrac{k-0}{0-5}\\\\\\m= -\dfrac{k}{5}\\\\\\m=-1\\\\\\-1= -\dfrac{k}{5} \\\\\\k=5](https://tex.z-dn.net/?f=m%3D+%5Cdfrac%7By_B-y_A%7D%7Bx_B-x_A%7D+%5C%5C%5C%5C%5C%5Cm%3D+%5Cdfrac%7Bk-0%7D%7B0-5%7D%5C%5C%5C%5C%5C%5Cm%3D+-%5Cdfrac%7Bk%7D%7B5%7D%5C%5C%5C%5C%5C%5Cm%3D-1%5C%5C%5C%5C%5C%5C-1%3D+-%5Cdfrac%7Bk%7D%7B5%7D+%5C%5C%5C%5C%5C%5Ck%3D5++)
Perguntas interessantes