Question

o 10°termo da P.G (9,27...)

Answer 1

$PG (9,27, ...)\\\\ a_1=9\\ q= 27:9=~3\\ n=10\\ a_{10}=?\\\\\\ a_n=a_1\times q^{n-1}\\\\ \\a_{10}=9\times 3^{10-1}\to\\\\ a_{10}=9\times 3^{9}\to\\\\ a_{10}=9\times 19683\to \\\\ \large\boxed{a_{10}=177147}\\\\\\\\ PG (9,27,81, 243, 729, 2187, 6561, 19683, 59049, 177147)$

Answer 2

Numa PG
                     $an=a1 q^{n-1}$
 
 Na PG em estudo
                       a1 = 9
                     a10 = ??
                         n = 10
                          r = $\frac{27}{9} =3$

                             $a10=9. 3^{10-1} \\ \\ a10=9.3^9 \\ \\ a10=9.19683 \\ \\ a10=177147$