Question

Números complexos ( / = Sobre)
Efetuar:
a) (2+3i)+(6+4i)
b) (6+5i)+(2-i)
c) (6+5i)-(2+3i)
d) (√2+i)-(√3+i)
e) (-1+2i)*(3+i)
f) (1/2+i)*(1/2-i)
g) 2+i/5+3i
h) 5+i/i

Answer 1

8 + 7i

8 - 4i

4 - 2i

V2 - V3

-3 - i + 6i + 2i^2 (2i^2 = 2 . -1)
-3 - 2 -i + 6i
-5 + 5i ←

1/4 - i/2 + i/2 - i^2(i^2 = -1)
1/4 + 1
5/4 ←

(2 + i)(5 - 3i) / (5 + 3i)(5 - 3i)
10 - 6i + 5i - 3i^2 / 25 - 9i^2
13 - i / 25 + 9
13/34 - i/34 ←

(5 + i)(-i) / i . -i
-5i - i^2 / - i^2
-5i + i ←