Question

Números complexos
Preciso da E resolvida por favor

Answer 1

$2x^2 - 2x+1=0\\ d=(-2)^2-4*2*1\\ d=4-8=-4\\ x= \frac{2 \frac{+}{-} \sqrt{-4} }{4} \\i^2=-1\\ \sqrt{-4}=\sqrt{4*(-1)}= \sqrt{4i^2} = 2i\\ x= \frac{2\frac{+}{-}2i}{4} \\ x_{1}= \frac{2+2i}{4} = \frac{1+i}{2}\\\ x_{2}=\frac{2-2i}{4} = \frac{1-i}{2}\\\\ S= \{ \frac{1+i}{2}, \frac{1-i}{2} \}$